Answer
$\frac{3}{4}$ and $y\ne5.$
Work Step by Step
$\frac{7}{y-5}\div\frac{28}{3y-15}=\frac{7}{y-5}\frac{3(y-5)}{28}=\frac{3}{4}$ and $y\ne5.$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 76
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