Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 56

Answer

$\frac{x-1}{x+2}$

Work Step by Step

$\frac{x^2-1}{x^2-4}*\frac{x^2-5x+6}{x^2-2x-3}=\frac{(x+1)(x-1)(x-2)(x-3)}{(x+2)(x-2)(x-3)(x+1)}=\frac{x-1}{x+2}$
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