Answer
$x^2-3$ and $x\ne-4.$
Work Step by Step
$\frac{x^3+4x^2-3x-12}{x+4}=\frac{x^2(x+4)-3(x+4)}{x+4}=\frac{(x+4)(x^2-3)}{x+4}=x^2-3$ and $x\ne-4.$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 49
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