Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - Exercise Set - Page 414: 55

Answer

$\frac{x+3}{x-2}$

Work Step by Step

$\frac{x^2-9}{x^2-x-6}\times\frac{x^2+5x+6}{x^2+x-6}=\frac{(x+3)(x-3)(x+2)(x+3}{(x-3)(x+2)(x+3)(x-2)}=\frac{x+3}{x-2}$
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