Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Review Exercises - Page 498: 73

Answer

$800$ cubic feet.

Work Step by Step

Step 1:- Translate the statement to form an equation. Let the volume of a pyramid be $V$, the height be $H$, and the area of its base be $A$. Because $V$ varies jointly as $H$ and $A$, we have: $\Rightarrow V=kHA$ ...... (1) Step 2:- Substitute the first set of values into the equation to find the value of $k$. The given values are $H=15$ feet ,$A=35$ square feet and $V=175$ cubic feet. Substitute into the equation (1). $\Rightarrow 175=k(15)(35)$ Simplify. $\Rightarrow 175=525k$ Divide both sides by $525$. $\Rightarrow \frac{175}{525}=\frac{525k}{525}$ Simplify. $\Rightarrow \frac{1}{3}=k$ Step 3:- Substitute the value of $k$ into the original equation. Substitute $k=\frac{1}{3}$ into the equation (1). $\Rightarrow V=\frac{1}{3}HA$ ...... (2) Step 4:- Solve the equation to find the required value. Substitute $H=20$ feet and $A=120$ square feet into the equation (2). $\Rightarrow V=\frac{1}{3}(20)(120)$ Simplify. $\Rightarrow V=800$ Hence, the volume of a pyramid is $800$ cubic feet.
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