Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Review Exercises - Page 498: 62

Answer

(a.) $C(x)=50,000+25x$. (b.) $\bar{C}(x)=\frac{50,000+25x}{x}$. (c.) $5,000$ graphing calculators.

Work Step by Step

Let the number of calculator manufactured be $x$. Fixed monthly cost $=\$50,000$. Cost of each calculator $=\$25$. Total cost of calculators $=25x$. (a.):- The cost function is equal to fixed monthly cost plus total cost of each calculator. $\Rightarrow C(x)=50,000+25x$ (b):- Average cost function $=\frac{Total \;cost}{Number\;of \;calculators}$ $\Rightarrow \bar{C}(x)=\frac{50,000+25x}{x}$ (c):- Replace $\bar{C}(x)$ by $35$ into average cost function. $\Rightarrow 35=\frac{50,000+25x}{x}$ Multiply both sides by $x$. $\Rightarrow 35x=\frac{50,000+25x}{x}\cdot x$ Simplify. $\Rightarrow 35x=50,000+25x$ Subtract $25x$ from both sides. $\Rightarrow 35x-25x=50,000+25x-25x$ Simplify. $\Rightarrow 10x=50,000$ Divide both sides by $10$. $\Rightarrow \frac{10x}{10}=\frac{50,000}{10}$ Simplify. $\Rightarrow x=5000$.
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