Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Review Exercises - Page 498: 68

Answer

$\$4935$.

Work Step by Step

Step 1:- Translate the statement to form a equation. Let the profit be $P$ and the number of product $N$. Because $P$ varies directly as $N$, we have: $\Rightarrow P=kN$ ...... (1) Step 2:- Substitute the first set of values into the equation (1) to find the value of $k$. The given values are $P=\$1175$ and $N=25$ products. Substitute into the equation (1). $\Rightarrow 1175=k(25)$ Divide both sides by $25$. $\Rightarrow \frac{1175}{25}=\frac{25k}{25}$ Simplify. $\Rightarrow 47=k$ Step 3:- Substitute the value of $k$ into the original equation. Substitute $k=47$ into the equation (1). $\Rightarrow P=47N$ ...... (2) Step 4:- Solve the equation to find the required value. Substitute $N=105$ into the equation (2). $\Rightarrow P=47(105)$ Simplify. $\Rightarrow P=4935$ Hence, the company's profit is $\$4935$.
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