Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Review Exercises - Page 498: 70

Answer

$440$ vibrations per second.

Work Step by Step

Step 1:- Translate the statement to form an equation. Let the pitch be $P$. and the wavelength be $W$. Because the pitch varies inversely as $W$, we have: $\Rightarrow P=\frac{k}{W}$ ...... (1) Step 2:- Substitute the first set of values into the equation to find the value of $k$. The given values are $P=\$660$ vibrations per second and $W=1.6$ feet. Substitute into the equation (1). $\Rightarrow 660=\frac{k}{1.6}$ Multiply both sides by $1.6$. $\Rightarrow 1.6\cdot 660=1.6\cdot \frac{k}{1.6}$ Simplify. $\Rightarrow 1056=k$ Step 3:- Substitute the value of $k$ into the original equation. Substitute $k=1056$ into the equation (1). $\Rightarrow P=\frac{1056}{W}$ ...... (2) Step 4:- Solve the equation to find the required value. Substitute $W=2.4$ feet into the equation (2). $\Rightarrow P=\frac{1056}{2.4}$ Simplify. $\Rightarrow P=440$ Hence, the pitch of a tone is $440$ vibrations per second.
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