Answer
$n=\frac{IR}{E-Ir}$
Work Step by Step
$I(R+nr)=nE\\IR+Inr=nE\\IR=nE-Inr\\IR=n(E-Ir)\\n=\frac{IR}{E-Ir}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Review Exercises - Page 498: 61
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