Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Review Exercises - Page 498: 72

Answer

$16$ hours.

Work Step by Step

Step 1:- Translate the statement to form an equation. Let the time required be $T$, the number of computers be $N$, and the number of workers be $W$. Because $T$ varies directly as $N$ and inversely as $W$, we have $\Rightarrow T=\frac{kN}{W}$ ...... (1) Step 2:- Substitute the first set of values into the equation to find the value of $k$. The given values are $N=30$ computers ,$W=6$ workers and $T=10$ hours. Substitute into the equation (1). $\Rightarrow 10=\frac{k(30)}{6}$ Simplify. $\Rightarrow 10=5k$ Divide both sides by $5$. $\Rightarrow \frac{10}{5}=\frac{5k}{5}$ Simplify. $\Rightarrow 2=k$ Step 3:- Substitute the value of $k$ into the original equation. Substitute $k=2$ into the equation (1). $\Rightarrow T=\frac{2N}{W}$ ...... (2) Step 4:- Solve the equation to find the required value. Substitute $W=5$ workers and $N=40$ computers into the equation (2). $\Rightarrow T=\frac{2(40)}{5}$ Simplify. $\Rightarrow T=16$ Hence, the time required is $16$ hours.
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