Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Review Exercises - Page 498: 60

Answer

$R=\frac{R_1R_2}{R_2+R_1}$.

Work Step by Step

To solve the formula for the variable $R$ means to isolate $R$ on one side of the given equation. First we multiply both sides by $RR_1R_2$ to clear fractions. $\Rightarrow RR_1R_2\cdot \left (\frac{1}{R}\right )=RR_1R_2\left (\frac{1}{R_1}+\frac{1}{R_2}\right )$ Use the distributive property. $\Rightarrow R_1R_2=R\left (\frac{R_1R_2}{R_1}+\frac{R_1R_2}{R_2}\right )$ Cancel common factors. $\Rightarrow R_1R_2=R(R_2+R_1)$ Divide both sides by $(R_2+R_1)$. $\Rightarrow \frac{R_1R_2}{(R_2+R_1)}=\frac{R(R_2+R_1)}{(R_2+R_1)}$ Simplify. $\Rightarrow \frac{R_1R_2}{(R_2+R_1)}=R$ $\Rightarrow R=\frac{R_1R_2}{R_2+R_1}$.
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