Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 362: 95

Answer

$\left (x+\frac{3}{7} \right )\left (x-\frac{1}{7} \right )$.

Work Step by Step

The given expression is $=x^2-\frac{3}{49}+\frac{2}{7}x$ Rearrange. $=x^2+\frac{2}{7}x-\frac{3}{49}$ Rewrite $\frac{2}{7}$ as $\frac{3}{7}-\frac{1}{7}$. $=x^2+\frac{3}{7}x-\frac{1}{7}x-\frac{3}{49}$ Factor. $=x\left (x+\frac{3}{7} \right )-\frac{1}{7} \left (x+\frac{3}{7} \right )$ $=\left (x+\frac{3}{7} \right )\left (x-\frac{1}{7} \right )$.
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