Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 362: 93

Answer

$(x-0.3)(x-0.2)$.

Work Step by Step

The given expression is $=x^2-0.5x+0.06$ Rewrite $-0.5x$ as $-0.3-0.2$. $=x^2-0.3x-0.2x+0.06$ Factor. $=x(x-0.3)-0.2(x-0.3)$ $=(x-0.3)(x-0.2)$.
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