Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 362: 94

Answer

$(x+0.4)(x-0.1)$.

Work Step by Step

The given expression is $=x^2+0.3x-0.04$ Rewrite $0.3x$ as $0.4-0.1$. $=x^2+0.4x-0.1x-0.04$ Factor. $=x(x+0.4)-0.1(x+0.4)$ $=(x+0.4)(x-0.1)$.
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