Answer
$(y^5+3)(2y^5+1)$.
Work Step by Step
The given expression is
$=2y^{10}+7y^5+3$
We can write
$=2(y^5)^2+7x^5+3$
Substitute $y^5=u$.
$=2(u)^2+7u+3$
Simplify.
$=2u^2+7u+3$
Rewrite $7u$ as $6u+1u$.
$=2u^2+6u+1u+3$
Factor.
$=2u(u+3)+1(u+3)$
$=(u+3)(2u+1)$.
Substitute back $u=y^5$.
$=(y^5+3)(2y^5+1)$.