Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 362: 92

Answer

$=(x-4)(3x-5)$.

Work Step by Step

The given expression is $=3(x-2)^{2}-5(x-2)-2$ Substitute $x-2=u$. $=3(u)^2-5u-2$ Simplify. $=3u^2-5u-2$ Rewrite $-5u$ as $-6u+1u$. $=3u^2-6u+1u-2$ Factor. $=3u(u-2)+1(u-2)$ $=(u-2)(3u+1)$. Substitute back $u=x-2$. $=((x-2)-2)(3(x-2)+1)$. Simplify. $=(x-2-2)(3x-6+1)$. $=(x-4)(3x-5)$.
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