Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 362: 91

Answer

$(2x-13)(x-2)$.

Work Step by Step

The given expression is $=2(x-3)^{2}-5(x-3)-7$ Substitute $x-3=u$. $=2(u)^2-5u-7$ Simplify. $=2u^2-5u-7$ Rewrite $-5u$ as $-7u+2u$. $=2u^2-7u+2u-7$ Factor. $=u(2u-7)+1(2u-7)$ $=(2u-7)(u+1)$. Substitute back $u=x-3$. $=(2(x-3)-7)((x-3)+1)$. Simplify. $=(2x-6-7)(x-3+1)$. $=(2x-13)(x-2)$.
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