Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 362: 90

Answer

$(x+2)(3x+5)$.

Work Step by Step

The given expression is $=3(x+1)^{2}-5(x+1)+2$ Substitute $x+1=u$. $=3(u)^2-5u+2$ Simplify. $=3u^2-5u+2$ Rewrite $5u$ as $3u+2u$. $=3u^2+3u+2u+2$ Factor. $=3u(u+1)+2(u+1)$ $=(u+1)(3u+2)$. Substitute back $u=x+1$. $=((x+1)+1)(3(x+1)+2)$. Simplify. $=(x+1+1)(3x+3+2)$. $=(x+2)(3x+5)$.
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