Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 362: 109

Answer

$(x+5)(x+3)$.

Work Step by Step

The given expression is $x^2+8x+15$ The trinomial is of the form $ax^2+bx+c$. By comparing the given expression with standard form we have. $a=1,b=8$ and $c=15$. Multiply $a$ and $c$ $a\cdot c = 1\cdot 15$ $a\cdot c = 15$ Now find the factors of $a\cdot c$ whose sum is equal to $b$. The factors are $5+3 =b = 8$. Rewrite the middle term $8x$ as $5x+3x$. $x^2+5x+3x+15$ Group terms. $(x^2+5x)+(3x+15)$ Factor from each group. $x(x+5)+3(x+5)$ Factor out $(x+5)$. $(x+5)(x+3)$. Hence, the factors are $x^2+8x+15 = (x+5)(x+3)$.
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