Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 362: 100

Answer

$-x^2y^3(5x-2y)(x-y)$.

Work Step by Step

The given expression is $=-5x^4y^3+7x^3y^4-2x^2y^5$ Factor out common term $-x^2y^3$. $=-x^2y^3(5x^2-7xy+2y^2)$ Rewrite term $-7xy$ as $-5xy-2xy$. $=-x^2y^3(5x^2-5xy-2xy+2y^2)$ Group terms. $=-x^2y^3[(5x^2-5xy)+(-2xy+2y^2)]$ Factor from each group. $=-x^2y^3[5x(x-y)-2y(x-y)]$ Factor out $(x-y)$. $=-x^2y^3(x-y)(5x-2y)$. Rearrange. $=-x^2y^3(5x-2y)(x-y)$.
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