Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - Chapter Review Exercises - Page 401: 49

Answer

$\frac{- 4 + \sqrt{ 10} }{ 3}\approx -0.279$, $\frac{- 4 - \sqrt{ 10} }{ 3}\approx -2.387$

Work Step by Step

Given \begin{equation} 3 x^2+8 x=-2. \end{equation} Rearrange the equation before applying the quadratic formula and determine the constants $a$, $b$, $c$: \begin{equation} \begin{aligned} 3 x^2+8 x&=-2\\ 3 x^2+8 x+2&=0\\ ax^2+bx+c&=0\\ a =3, b= 8, c&= 2. \end{aligned} \end{equation} The quadratic formula gives: \begin{equation} \begin{aligned} x&=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\ n &==\frac{-8 \pm \sqrt{8^2-4 \cdot 3 \cdot 2}}{2 \cdot 3}\\ &=\frac{-8 \pm \sqrt{40} }{6}\\ &=\frac{-8 \pm \sqrt{4\cdot 10} }{6}\\ &=\frac{-2\cdot 4 \pm 2 \sqrt{ 10} }{2\cdot 3}\\ &=\frac{- 4 \pm \sqrt{ 10} }{\cdot 3}. \end{aligned} \end{equation} The solution is: \begin{equation} x=\frac{- 4 + \sqrt{ 10} }{3}\approx -0.279 ,\quad x=\frac{- 4 - \sqrt{ 10} }{ 3}\approx -2.387. \end{equation}
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