Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - Chapter Review Exercises - Page 401: 45

Answer

There are no real solutions to this equation.

Work Step by Step

The quadratic equation is one that is in the form $ax^2 + bx + c = 0$, where $a$, $b$, and $c$ are real numbers. We are asked to solve the quadratic equation given using the quadratic formula, which is given by the formula: $x = \frac{-b ± \sqrt {b^2 - 4ac}}{2a}$ Let's plug our values into this formula to solve for $x$: $x = \frac{-6 ± \sqrt {(6)^2 - 4(1)(18)}}{2(1)}$ Let's simplify: $x = \frac{-6 ± \sqrt {36 - 72}}{2}$ Simplify what is under the radical sign: $x = \frac{-6 ± \sqrt {-36}}{2}$ Because we will have to take the square root of a negative number, there are no real solutions to this equation.
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