Answer
$-13$ ; $13$
Work Step by Step
Given \begin{equation}
t^2=169.
\end{equation} Apply the square root property to solve.
\begin{equation}
\begin{aligned}
t^2&=169\\
t&=\pm \sqrt{169}\\
t&=\pm 13.
\end{aligned}
\end{equation}
Check \begin{equation}
\begin{aligned}
(-13)^2&\stackrel{?}{=}169\\
169&=169\checkmark\\\\
13^2&\stackrel{?}{=}169\\
169&=169\checkmark.
\end{aligned}
\end{equation} Both solutions are correct, so the answer is $$t=-13,\quad t=13.$$
