Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-8 - Cumulative Review - Page 678: 9

Answer

$c = -6$

Work Step by Step

$7c^{3} - 120 = -1632$ $7c^{3} = -1632 + 120$ $7c^{3} = -1512$ $c^{3} = - 216$ $c = (-216)^{\frac{1}{3}}$ $c = -6$ Check: $7c^{3} - 120 \overset{?}{=} -1632$ $7(-6)^{3} - 120 \overset{?}{=} -1632$ $7(-216) - 120 \overset{?}{=} -1632$ $-1512 - 120 \overset{?}{=} -1632$ $-1632 = -1632$
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