Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-8 - Cumulative Review - Page 678: 21

Answer

No solution

Work Step by Step

Given $$\begin{cases} 3 x+6 y=20 \\ 4 y=-2 x+15. \end{cases}$$ Write $y$ as a function of $x$ in each of the two lines. \begin{equation} \begin{aligned} 3 x+6 y&=20\\ y&=\frac{20}{6}-\frac{3x}{6}\\ \implies y&= -\frac{1}{2}x+ \frac{10}{3}\\ 4 y&=-2 x+15\\ \implies y&= -\frac{1}{2}x+\frac{15}{4}. \end{aligned} \end{equation} At this point, we see that the lines are parallel and independent. This means that there is no common point to the lines. Hence, there is no solution for the system. . See the graph of the functions for further proof.
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