Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-8 - Cumulative Review - Page 678: 28

Answer

Domain: all real numbers except $x=-2$ and $x=-4$

Work Step by Step

Given \begin{equation} f(x)=\frac{x+2}{x^2+6 x+8}. \end{equation} We first note that this a rational function and that its domain must exclude the values of $x$ that make the denominator equal to zero. We must find the zeros of the denominator and exclude it from the domain of the function. Set the denominator to zero and solve for $x$. \begin{equation} \begin{aligned} x^2+6 x+8&=0\\ x^2+2x+4x+8&= 0\\ x(x+2)+4(x+2)&=0\\ (x+2)(x+4)&= 0\\ \therefore x&= -2\\ x&= -4. \end{aligned} \end{equation} \begin{equation} \text { Domain: } x \text { is all real numbers except } x=-2 \text { and } x=-4. \end{equation}
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