Answer
$27^{\frac{2}{3}}=9$
Work Step by Step
RECALL:
$a^{\frac{b}{c}}=\sqrt[c]{a^b}$
Thus,
$27^{\frac{2}{3}}
\\=\sqrt[3]{27^2}
\\=\sqrt[3]{(3^3)^2}
\\=\sqrt[3]{3^{6}}
\\=\sqrt[3]{(3^2)^3}
\\=3^2
\\=9$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 9 - Section 9.2 - Inverse Functions - Exercise Set - Page 551: 54
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