Answer
$f^{-1}=(x-6)^{1/3}$
Work Step by Step
$f(x)=x^3+6$
$y=x^3+6$
$x=y^3+6$
$x-6=y^3+6-6$
$x-6=y^3$
$(x-6)^{1/3}=(y^3)^{1/3}$
$(x-6)^{1/3} = y$
$f^{-1}=(x-6)^{1/3} $
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 9 - Section 9.2 - Inverse Functions - Exercise Set - Page 551: 49
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