Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.2 - Inverse Functions - Exercise Set - Page 551: 28

Answer

$f^{-1}(x)=-2x+4$ The graph of both functions is shown below:

Work Step by Step

$f(x)=-\dfrac{1}{2}x+2$ Substitute $f(x)$ by $y$: $y=-\dfrac{1}{2}x+2$ Solve this expression for $x$. Begin by taking $2$ to the left side: $y-2=-\dfrac{1}{2}x$ $-\dfrac{1}{2}x=y-2$ Take $-2$ to multiply the right side: $x=(-2)(y-2)$ $x=-2y+4$ Interchange $x$ and $y$: $y=-2x+4$ Substitute $y$ by $f^{1}(x)$: $f^{-1}(x)=-2x+4$
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