Answer
$f^{-1}(x)=x^{3}$
Work Step by Step
$f(x)=\sqrt[3]{x}$
Substitute $f(x)$ by $y$
$y=\sqrt[3]{x}$
Solve for $x$ by raising both sides to the cubic power:
$y^{3}=(\sqrt[3]{x})^{3}$
$y^{3}=x$
$x=y^{3}$
Interchange $x$ and $y$:
$y=x^{3}$
Substitute $y$ by $f^{-1}(x)$
$f^{-1}(x)=x^{3}$