Answer
Please see the graph.
The blue line is the inverse function, and the red line is the original function.
Work Step by Step
The original function has points $(2,0)$, $(0,3)$, and $(4, -3)$.
$y=mx+b$
$m=(y2-y1)/(x2-x1)$
$m=(3-0)/(0-2)$
$m=3/-2$
$m=-3/2$
$y=mx+b$
$y=-3/2*x+b$
$0=-3/2*2+b$
$0=-3+b$
$0+3=-3+b+3$
$3=b$
$y=-3/2x+3$
Inverse:
$y=-3/2x+3$
$x=-3/2y+3$
$x-3=-3/2y+3-3$
$x-3=-3/2y$
$(x-3)*-2/3=-3/2*y*-2/3$
$-2/3*(x-3) = y$
$-2/3x+2 =y$
