Answer
$f^{-1}(x)=\sqrt[3]{x}$
The graph of both functions is shown below:
Work Step by Step
$f(x)=x^{3}$
Substitute $f(x)$ by $y$:
$y=x^{3}$
Solve for $x$. Do so by taking the cubic root of both sides of the equation:
$\sqrt[3]{x^{3}}=\sqrt[3]{y}$
$x=\sqrt[3]{y}$
Interchange $x$ and $y$:
$y=\sqrt[3]{x}$
Substitute $y$ by $f^{-1}(x)$:
$f^{-1}(x)=\sqrt[3]{x}$