Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.2 - Inverse Functions - Exercise Set - Page 551: 52

Answer

$49^{\frac{1}{2}}=7$

Work Step by Step

RECALL: For any real number $a\ge 0$, $a^{\frac{1}{2}}= \sqrt{a}$ Thus, $49^{\frac{1}{2}}=\sqrt{49} = \sqrt{7^2} = 7$
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