Answer
$f^{-1} =(x+5)^{1/3}$
Work Step by Step
$f(x)=x^3-5$
$y=x^3-5$
$x=y^3-5$
$x+5=y^3-5+5$
$x+5=y^3$
$(x+5)^{1/3}=(y^3)^{1/3}$
$(x+5)^{1/3} = y$
$f^{-1} =(x+5)^{1/3}$
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