Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.2 - Inverse Functions - Exercise Set - Page 551: 53

Answer

$16^{\frac{3}{4}}=8$

Work Step by Step

RECALL: $a^{\frac{b}{c}}=\sqrt[c]{a^b}$ Thus, $16^{\frac{3}{4}} \\=\sqrt[4]{16^3} \\=\sqrt[4]{(2^4)^3} \\=\sqrt[4]{2^{12}} \\=\sqrt[4]{(2^3)^4} \\=2^3 \\=8$
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