Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.4 - Nonlinear Inequalities in One Variable - Exercise Set - Page 511: 50

Answer

$(3,15]$

Work Step by Step

$4x/(x-3) \geq 5$ $4x/(x-3)-5 \geq 5-5$ $4x/(x-3)-5 \geq 0$ $4x/(x-3)-5*(x-3)/(x-3) \geq 0$ $4x/(x-3) -5x+15/(x-3) \geq 0$ $(4x-5x+15)/(x-3) \geq 0$ $(-x+15)/(x-3) \geq 0$ The denominator is zero when $x=3$, and the numerator is zero when $x=15$. We have three sections: $(−∞,3)$, $(3,15)$, and $(15,∞)$. We need to test one value for x in each section to determine if the section would be a solution set. Since we have the $\geq$ sign, we include the end points and use brackets instead of parentheses. Let $x=0$, $x=5$, and $x=20$ $x=0$ $4x/(x-3) \geq 5$ $4*0/(0-3) \geq 5$ $0/-3 \geq 5$ $0 \geq 5$ (false) $x=5$ $4x/(x-3) \geq 5$ $4*5/(5-3) \geq 5$ $20/2 \geq 5$ $10 \geq 5$ (true) $x=20$ $4x/(x-3) \geq 5$ $4*20/(20-3) \geq 5$ $80/17 \geq 5$ (false)
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