Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.4 - Nonlinear Inequalities in One Variable - Exercise Set - Page 511: 47

Answer

$(−∞,1)$ U $(2,∞)$

Work Step by Step

$-1/(x-1) > -1$ $-1/(x-1)*(x-1) > -1*(x-1)$ $-1 > -1(x-1)$ $-1 > -x +1 $ $-1+1+x > -x+1+1+x$ $x > 2$ The denominator is zero when $x=1$. We have three sections: $(−∞,1)$, $(1,2)$, and $(2,∞)$. We need to test one value for x in each section to determine if the section would be a solution set. Since we have the $>$ sign, we exclude the end points and use parentheses instead of brackets. Let $x=0$, $x=1.5$, and $x=3$ $x=0$ $-1/(x-1) > -1$ $-1/(0-1) > -1$ $-1/-1 > -1$ $1 > -1$ (true) $x=1.5$ $-1/(x-1) > -1$ $-1/(1.5-1) > -1$ $-1/.5>-1$ $-2 > -1$ (false) $x=3$ $-1/(x-1) > -1$ $-1/(3-1) > -1$ $-1/2 > -1$ (true)
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