Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.4 - Nonlinear Inequalities in One Variable - Exercise Set - Page 511: 48

Answer

$(-4,-2)$

Work Step by Step

$4/(y+2) < -2$ $4/(y+2) y$ The denominator is zero when $y=-2$. We have three sections: $(−∞,-4)$, $(-4,-2)$, and $(-2,∞)$. We need to test one value for x in each section to determine if the section would be a solution set. Since we have the $
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