Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.4 - Nonlinear Inequalities in One Variable - Exercise Set - Page 511: 42

Answer

$(−∞,-10)$ U $(10,∞)$

Work Step by Step

$(x+10)/(x-10) > 0$ The denominator is zero when $x=10$, and the numerator is zero when $x=-10$. We have three sections: $(−∞,-10)$, $(-10, 10)$, and $(10,∞)$. We need to test one value for x in each section to determine if the section would be a solution set. Since we have the $>$ sign, we exclude the end points and use parentheses instead of brackets. Let $x=-11$, $x=1$, and $x=11$ $x=-11$ $(x+10)/(x-10) > 0$ $(-11+10)/(-11-10) > 0$ $-1/-21 >0$ $1/21 >0$ (true) $x=1$ $(x+10)/(x-10) > 0$ $(1+10)/(1-10) > 0$ $11/-9 >0$ $-11/9 > 0$ (false) $x=11$ $(x+10)/(x-10) > 0$ $(11+10)/(11-10) > 0$ $21/1 > 0$ $21 >0$ (true)
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