Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.4 - Nonlinear Inequalities in One Variable - Exercise Set - Page 511: 43

Answer

$(−∞,-4)$ U $(5,∞)$

Work Step by Step

$(x-5)/(x+4) \ge 0$ The denominator is zero when $x=-4$, and the numerator is zero when $x=5$. We have three sections: $(−∞,-4)$, $(-4, 5)$, and $(5,∞)$. We need to test one value for x in each section to determine if the section would be a solution set. Since we have the $\ge$ sign, we include the end points and use brackets instead of parentheses. Let $x=-10$, $x=0$, and $x=10$ $x=-10$ $(x-5)/(x+4) \ge 0$ $(-10-5)/(-10+4) \ge 0$ $-15/-6 \ge 0$ $5/2 \ge 0$ (true) $x=0$ $(x-5)/(x+4) \ge 0$ $(0-5)/(0+4) \ge 0$ $-5/4 \ge 0$ (false) $x=10$ $(x-5)/(x+4) \ge 0$ $(10-5)/(10+4) \ge 0$ $5/14 \ge 0$ (true)
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