Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 473: 50c

Answer

$\frac{11\sqrt[3] 3}{10}$

Work Step by Step

$\frac{\sqrt[3] 81}{10} + \sqrt[3] \frac{192}{125}$ Using properties of radicals, $= \frac{\sqrt[3] 81}{10} +\frac{\sqrt[3] 192}{\sqrt[3] 125}$ $= \frac{\sqrt[3] (27 \times 3)}{10} +\frac{\sqrt[3](3 \times 64) }{\sqrt[3]5^{3}}$ $= \frac{\sqrt[3]( 3 ^{3} \times 3)}{10} +\frac{\sqrt[3](3 \times 4^{3}) }{5}$ $= \frac{3 \sqrt[3] 3}{10} +\frac{ 4 \sqrt[3]3 }{5}$ Taking LCD, $= \frac{ 3\sqrt[3] 3 + 8 \sqrt[3]3 }{10} $ $= \frac{11 \sqrt[3] 3}{10} $
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