Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 473: 34a

Answer

$\dfrac{9x-2y}{3x^2y^2}$

Work Step by Step

Using the $LCD= 3x^2y^2 ,$ the given expression, $ \dfrac{3}{xy^2}-\dfrac{2}{3x^2y} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{3x(3)-y(2)}{3x^2y^2} \\\\= \dfrac{9x-2y}{3x^2y^2} .\end{array}
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