Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 473: 35a

Answer

$\dfrac{x(x-2)}{2(x+2)}$

Work Step by Step

The given expression, $ \dfrac{\dfrac{5x}{x+2}}{\dfrac{10}{x-2}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{5x}{x+2}\div\dfrac{10}{x-2} \\\\= \dfrac{5x}{x+2}\cdot\dfrac{x-2}{10} \\\\= \dfrac{\cancel{5}x}{x+2}\cdot\dfrac{x-2}{\cancel{5}\cdot2} \\\\= \dfrac{x(x-2)}{2(x+2)} .\end{array}
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