Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 473: 41

Answer

no solution

Work Step by Step

By cross-multiplication, the given expression, $ \dfrac{x+6}{x-2}=\dfrac{2(x+2)}{x-2} ,$ is equivalent to \begin{array}{l}\require{cancel} (x+6)(x-2)=2(x+2)(x-2) \\\\ x(x)+x(-2)+6(x)+6(-2)=2(x^2-4) \\\\ x^2-2x+6x-12=2x^2-8 \\\\ (x^2-2x^2)+(-2x+6x)+(-12+8)=0 \\\\ -x^2+4x-4=0 \\\\ x^2-4x+4=0 \\\\ (x-2)^2=0 \\\\ \sqrt{(x-2)^2}=\sqrt{0} \\\\ x-2=0 \\\\ x=2 .\end{array} Upon checking, $x=2$ does not satisfy the original equation. Hence, there is $\text{ no solution .}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.