Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 473: 50b

Answer

$3b\sqrt[3]{2a}$

Work Step by Step

Using the properties of radicals, the given expression, $ \sqrt[3]{128ab^3}-3\sqrt[3]{2ab^3}+b\sqrt[3]{16a} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt[3]{64b^3\cdot2a}-3\sqrt[3]{b^3\cdot2a}+b\sqrt[3]{8\cdot2a} \\\\= \sqrt[3]{(4b)^3\cdot2a}-3\sqrt[3]{(b)^3\cdot2a}+b\sqrt[3]{(2)^3\cdot2a} \\\\= 4b\sqrt[3]{2a}-3b\sqrt[3]{2a}+2b\sqrt[3]{2a} \\\\= 3b\sqrt[3]{2a} .\end{array}
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