Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 473: 49

Answer

$\dfrac{x-4}{5\sqrt{x}-10}$

Work Step by Step

Multiplying by the conjugate of the numerator, the rationalized-numerator form of the given expression, $ \dfrac{\sqrt[]{x}+2}{5} ,$ is \begin{array}{l}\require{cancel} \dfrac{\sqrt[]{x}+2}{5}\cdot\dfrac{\sqrt[]{x}-2}{\sqrt[]{x}-2} \\\\= \dfrac{(\sqrt[]{x})^2-2^2}{5\sqrt{x}-10} \\\\= \dfrac{x-4}{5\sqrt{x}-10} .\end{array}
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