Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 473: 44

Answer

$a=\dfrac{2A-bh}{h}$

Work Step by Step

Using cross-multiplication and the properties of equality, in terms of $ a ,$ the given equation, $ A=\dfrac{h(a+b)}{2} $ is equivalent to \begin{array}{l}\require{cancel} 2A=h(a+b) \\\\ 2A=ah+bh \\\\ 2A-bh=ah \\\\ \dfrac{2A-bh}{h}=a \\\\ a=\dfrac{2A-bh}{h} .\end{array}
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