Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 473: 37

Answer

$2x^2-x+4$

Work Step by Step

The given expression, $ (10x^3-5x^2+20x)\div(5x) ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{10x^3}{5x}-\dfrac{5x^2}{5x}+\dfrac{20x}{5x} \\\\= 2x^2-x+4 .\end{array}
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