Answer
$2x^2-x+4$
Work Step by Step
The given expression, $
(10x^3-5x^2+20x)\div(5x)
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{10x^3}{5x}-\dfrac{5x^2}{5x}+\dfrac{20x}{5x}
\\\\=
2x^2-x+4
.\end{array}
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