Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Cumulative Review - Page 473: 40

Answer

$4y^2-1+\dfrac{9}{y-3}$

Work Step by Step

Using the synthetic division method below, then \begin{array}{l}\require{cancel} ( 4y^3-12y^2-y+12 )\div( y-3 ) \\= 4y^2-1+\dfrac{9}{y-3} .\end{array}
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