Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 405: 96

Answer

$\dfrac{2x}{x-2}$

Work Step by Step

The given expression, $ \dfrac{2}{1-\dfrac{2}{x}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{2}{\dfrac{x-2}{x}} \\\\= 2\div\dfrac{x-2}{x} \\\\= 2\cdot\dfrac{x}{x-2} \\\\= \dfrac{2x}{x-2} .\end{array}
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